# Desimal Berulang untuk suatu Numerator

### Abstract

Let π denote a positive integer relatively prime to 10 and π be natural

number less than π and relatively prime to π. Let the period of π

π

be ππ

with π > 1. Break the repeating block of ππ digits up into π sub blocks,

each of length π, and let π΅(ππ, π, π) denote the sum of these π blocks.

In 1836 has been proved and re-proofed in 2013 that if π is a prime

greater than 5, and the period of 1

π

is 2π, then π΅(π1, π, 2) = 10π β 1. In

2004, has been showed that if π is a prime greater than 5, and the period

of 1

π

is 3π, then π΅(π1, π, 3) = 10π β 1. In 2005, also was showed that if

π is a prime greater than 5, and the period of 1

π

is ππ, then π΅(π1, π, 3) is

multiply of 10π β 1. In 2007, study of repeating decimal of 1

π

is

expanded, that π don't have to prime greater than 5, but just relatively

prime to 10. In this paper, will be investigated property of repeating

decimal of π

π

with π don't have to equal to 1, but enough less than π

and relatively prime to π.